Example 1 — Special ratios
\(\arctan(1)=\tfrac{\pi}{4}=45^\circ\), \(\arctan(\sqrt{3})=\tfrac{\pi}{3}=60^\circ\), \(\arctan(-1)=-\tfrac{\pi}{4}=-45^\circ\).
Compute \(\theta=\arctan(x)\) (principal value). Enter the tangent value and press Calculate.
\( \text{Definition: } \theta=\arctan(x) \text{ is the angle with } \tan(\theta)=x,\; \theta\in(-\tfrac{\pi}{2},\,\tfrac{\pi}{2}). \)
\( \text{Common values: } \arctan(0)=0,\; \arctan(1)=\tfrac{\pi}{4},\; \arctan(\sqrt{3})=\tfrac{\pi}{3},\; \arctan(1/\sqrt{3})=\tfrac{\pi}{6}. \)
\( \text{Tip: } x=\tfrac{\text{opposite}}{\text{adjacent}} \text{ in a right triangle; signs determine } \theta\in(-\tfrac{\pi}{2},\,\tfrac{\pi}{2}). \)
An Inverse Tangent Calculator evaluates \(\arctan(x)\) (also written \(\tan^{-1}(x)\)) to convert a slope or ratio into an angle. The principal-value function maps real inputs to angles in the open interval \((-\tfrac{\pi}{2},\,\tfrac{\pi}{2})\). In right-triangle terms, \(x=\tfrac{\text{opposite}}{\text{adjacent}}\) and \(\theta=\arctan(x)\). For coordinate geometry, the two-argument form \(\operatorname{atan2}(y,x)\) returns the correct quadrant of the direction angle from the origin to \((x,y)\). This tool handles exact values when recognizable (e.g., \(\arctan(1)=\tfrac{\pi}{4}\)) and produces high-precision decimals otherwise. It can switch units (degrees ↔ radians), apply identities to simplify expressions, and show derivations clearly.
The calculator detects domain issues, explains principal values, and addresses common quadrant pitfalls by recommending \(\operatorname{atan2}\) for vectors. It displays unit conversions, exact symbolic outcomes for special angles, and numerical approximations with chosen precision. Advanced options include combining angles using addition formulas, differentiating \(\arctan(x)\) for calculus contexts, and interpreting negative or large inputs. For modeling, it interprets slopes from lines or regressions: given a slope \(m\), the inclination is \(\arctan(m)\) (or \(\operatorname{atan2}(\Delta y,\Delta x)\) for segment endpoints). The output includes step-by-step algebra and a concise summary of angle, unit, quadrant, and any simplifications used.
Definition & range: \[ \theta=\arctan(x)\in\left(-\frac{\pi}{2},\,\frac{\pi}{2}\right),\qquad \tan(\theta)=x. \]
Unit conversions: \[ \theta_{\deg}=\theta_{\text{rad}}\cdot\frac{180}{\pi},\qquad \theta_{\text{rad}}=\theta_{\deg}\cdot\frac{\pi}{180}. \]
Two-argument angle (correct quadrant): \[ \theta=\operatorname{atan2}(y,x)= \begin{cases} \arctan\!\left(\frac{y}{x}\right), & x>0\\[4pt] \arctan\!\left(\frac{y}{x}\right)+\pi, & x<0,\ y\ge0\\[4pt] \arctan\!\left(\frac{y}{x}\right)-\pi, & x<0,\ y<0\\[4pt] \tfrac{\pi}{2}, & x=0,\ y>0\\[4pt] -\tfrac{\pi}{2}, & x=0,\ y<0 \end{cases} \]
Inverse/identity relations: \[ \tan(\arctan x)=x,\qquad \arctan(\tan\theta)=\theta+k\pi \text{ (principal value in }(-\tfrac{\pi}{2},\tfrac{\pi}{2})). \]
Addition formula (branch-aware): \[ \arctan a+\arctan b=\arctan\!\left(\frac{a+b}{1-ab}\right)\ (\text{adjust by }\pm\pi\ \text{when }ab>1\ \text{or quadrants differ}). \]
Derivative: \[ \frac{d}{dx}\arctan(x)=\frac{1}{1+x^2}. \]
\(\arctan(1)=\tfrac{\pi}{4}=45^\circ\), \(\arctan(\sqrt{3})=\tfrac{\pi}{3}=60^\circ\), \(\arctan(-1)=-\tfrac{\pi}{4}=-45^\circ\).
Line with slope \(m=\tfrac{3}{4}\): inclination \(\theta=\arctan(\tfrac{3}{4})\approx 0.6435\ \text{rad}\approx36.87^\circ\).
For \((x,y)=(-3,-3)\): \(\theta=\operatorname{atan2}(-3,-3)=-\tfrac{3\pi}{4}=-135^\circ\) (third quadrant reference, reported in \((-\pi,\pi]\)).
\(\arctan(2)+\arctan(1)=\arctan\!\big(\tfrac{3}{-1}\big)=-\arctan(3)\). Adjust by \(\pi\) for a positive acute result: \( \pi-\arctan(3)\).
It returns principal values in \((-\tfrac{\pi}{2},\,\tfrac{\pi}{2})\), excluding the endpoints.
Use \(\operatorname{atan2}\) to get the correct quadrant automatically, especially when \(x\le0\) or \(x=0\).
Multiply radians by \(\tfrac{180}{\pi}\) to get degrees and degrees by \(\tfrac{\pi}{180}\) to get radians.
Because \(\arctan\) returns principal values; add/subtract multiples of \(\pi\) to map to your desired coterminal angle.
Yes, for recognizable inputs (e.g., \(1,\ \sqrt{3}\)); otherwise it provides high-precision decimal approximations.
Fractions are handled exactly; signs are preserved. The angle is negative when the ratio is negative.