Instantaneous Rate of Change Calculator
Find derivative at a point instantly: enter function f(x) and x-value, view steps, formula preview, and precise numeric slope output.
Equation Preview
Helping Notes
- Instantaneous rate at x=a equals the derivative value f′(a), the slope of the tangent line to y=f(x) at x=a.
- Definition: f′(a) = limh→0 [f(a+h) − f(a)] / h = limx→a [f(x) − f(a)] / (x − a).
- This tool auto-differentiates f(x) and evaluates exactly where possible (e.g., π), otherwise to high precision.
- Tangent line shown uses y = f(a) + f′(a)·(x − a).
Results
Instantaneous Rate f′(a)
Values & Derivative
Tangent Line at x=a
Error
What is Instantaneous Rate of Change Calculator?
An Instantaneous Rate of Change Calculator finds the derivative of a function at a specific point, which equals the slope of the tangent line to its graph there. Conceptually, it is the limit of average rates over shrinking intervals. If \(f\) is differentiable at \(a\), the instantaneous rate (denoted \(f'(a)\)) is defined by the limit below and represents how quickly \(f(x)\) changes per unit of \(x\) at that exact location.
Compare with the average rate of change on an interval \([a,b]\):
About the Instantaneous Rate of Change Calculator
This tool accepts a function \(f(x)\) and a point \(a\), then returns the derivative value \(f'(a)\), tangent slope, optional linearization, and supporting steps. It can differentiate symbolically using standard rules or numerically when symbolic differentiation is difficult. A stable numerical estimate uses the symmetric difference quotient with a small step size \(h\):
When symbolic mode is enabled, common rules are applied:
How to Use this Instantaneous Rate of Change Calculator
- Enter \(f(x)\) (e.g., x^3 - 4x + 1) and the point \(a\) (e.g., 2).
- Choose symbolic or numerical differentiation and, for numeric mode, a small step \(h\) (the default works well).
- Click calculate to compute \(f'(a)\), the tangent slope, and optional linear approximation.
- Review the step-by-step working: applied rules, simplified derivatives, and any numerical estimates.
- Copy the results and steps for homework, lab reports, or engineering documentation.
Examples
Example 1: Polynomial
For \(f(x)=x^3\) at \(a=2\):
Example 2: Trigonometric
For \(f(x)=\sin x\) at \(a=\tfrac{\pi}{6}\):
Example 3: Numerical approximation
For \(f(x)=\ln x\) at \(a=1\) using a small \(h\):
FAQs
What does instantaneous rate of change represent?
It’s the derivative at a point—the slope of the tangent line and the best linear predictor of local behavior.
How is it different from average rate of change?
Average rate uses a finite interval; instantaneous rate is the limit as the interval shrinks to zero.
What units does \(f'(a)\) have?
Output units are “units of \(f\) per unit of \(x\),” e.g., meters per second or dollars per item.
Can the derivative be negative?
Yes. A negative value means the function is decreasing at that point; zero indicates a horizontal tangent.
What if the function isn’t differentiable at \(a\)?
Corners, cusps, discontinuities, and vertical tangents may prevent a derivative from existing at that point.
Which differentiation rules does the tool use?
Power, product, quotient, and chain rules; plus known derivatives of standard functions like exponentials and trig.
How accurate is the numerical estimate?
Very accurate for smooth functions and small \(h\); the symmetric difference reduces truncation error.
Can I get the tangent line equation?
Yes. Use \(y=f(a)+f'(a)(x-a)\) to form the point-slope equation of the tangent.
Is this useful in physics?
Absolutely. Velocity is the instantaneous rate of change of position; acceleration is the derivative of velocity.
What about economics applications?
Marginal cost and marginal revenue are instantaneous rates—derivatives of cost and revenue with respect to quantity.
Can I differentiate piecewise functions?
Yes, but continuity and matching one-sided derivatives at the point must be checked.
Does scaling \(x\) or \(f\) affect the derivative?
Scaling multiplies \(f'(a)\) accordingly: \(d(\alpha f)/dx=\alpha f'\); rescaling \(x\) introduces a constant factor via the chain rule.
How do I verify my result?
Compare symbolic and numerical answers, or check against the limit definition with a small \(h\).