Example 1 — Find Final Pressure
\(P_1=1.00\ \mathrm{atm}, V_1=2.50\ \mathrm{L}, T_1=300\ \mathrm{K}; V_2=3.10\ \mathrm{L}, T_2=350\ \mathrm{K}\).
Combined Gas Law Calculator solves P1V1/T1 = P2V2/T2, handles unit conversions, Kelvin temperatures, quick scenarios, step-by-step equation previews for students.
P₁V₁/T₁ = P₂V₂/T₂
A Combined Gas Law Calculator computes any one unknown variable in the relationship between pressure \(P\), volume \(V\), and absolute temperature \(T\) for a fixed amount of gas:
By providing the other five values, users can quickly find the final pressure, volume, or temperature. The model assumes constant moles and ideal gas behavior. Using absolute temperatures (Kelvin) and consistent units ensures accurate results for classroom exercises, lab experiments, or real-world estimates like tank refills or temperature-driven pressure changes.The combined gas law merges Boyle’s Law (\(PV=\text{const}\) at constant \(T\)), Charles’s Law (\(V/T=\text{const}\) at constant \(P\)), and Gay-Lussac’s Law (\(P/T=\text{const}\) at constant \(V\)) into one equation for two states of the same gas sample.
The calculator emphasizes unit consistency: pressure (atm, bar, kPa, mmHg), volume (L, mL), and absolute temperature (K). Celsius or Fahrenheit inputs are converted automatically:
Assumptions include no phase change, constant moles, and ideal gas behavior. For extreme pressures or very low temperatures, non-ideal corrections (e.g., van der Waals) may be necessary.
Combined Gas Law (two states, constant moles):
Solving for unknowns:
Temperature conversions:
\(P_1=1.00\ \mathrm{atm}, V_1=2.50\ \mathrm{L}, T_1=300\ \mathrm{K}; V_2=3.10\ \mathrm{L}, T_2=350\ \mathrm{K}\).
\(P_1=750\ \mathrm{mmHg}=0.9868\ \mathrm{atm}, V_1=500\ \mathrm{mL}, T_1=295\ \mathrm{K}; P_2=1.20\ \mathrm{atm}, T_2=320\ \mathrm{K}\).
\(P_1=2.0\ \mathrm{bar}, V_1=1.2\ \mathrm{L}, T_1=280\ \mathrm{K}; P_2=1.0\ \mathrm{bar}, V_2=2.0\ \mathrm{L}\).
Yes. Convert all temperatures to Kelvin; using °C or °F directly gives incorrect results.
No. Ensure consistent pressure units (atm, mmHg, kPa, bar) for state 1 and 2.
Use the combined gas law to relate two states of the same sample (constant moles). Use \(PV=nRT\) when calculating moles is required.
It assumes the gas amount is constant; no leaks or mass transfer between states.
No. Convert both volumes to the same unit before calculation.
Phase changes violate the assumptions; the law does not apply across phase transitions.
Use \(T_\mathrm{K}=T_{^\circ\mathrm{C}}+273.15\) or \(T_\mathrm{K}=\frac{5}{9}(T_{^\circ\mathrm{F}}-32)+273.15\).
No. Deviations occur at high pressure or low temperature; real-gas corrections like van der Waals are needed in such cases.
Yes. Provide the other five; rearranged formulas for \(P_2\), \(V_2\), or \(T_2\) are available above.
\(1\ \mathrm{atm}=760\ \mathrm{mmHg}=101.325\ \mathrm{kPa}\approx1.01325\ \mathrm{bar}\).
Match the precision of input values; typically 2–3 significant figures in introductory problems.
Yes. Apply the law to each component if the amount is fixed and interactions are negligible.